X^2+120x-3256=0

Solution for X^2+120x-3256=0 equation:

X^2+120X-3256=0

a = 1; b = 120; c = -3256;
Δ = b2-4ac
Δ = 1202-4·1·(-3256)
Δ = 27424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27424}=\sqrt{16*1714}=\sqrt{16}*\sqrt{1714}=4\sqrt{1714}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-4\sqrt{1714}}{2*1}=\frac{-120-4\sqrt{1714}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+4\sqrt{1714}}{2*1}=\frac{-120+4\sqrt{1714}}{2}
$